Bash script

Security

• about variable quotes https://unix.stackexchange.com/questions/171346/security-implications-of-forgetting-to-quote-a-variable-in-bash-posix-shells

Parameter substitution

• from https://tldp.org/LDP/abs/html/parameter-substitution.html
• and https://www.cyberciti.biz/tips/bash-shell-parameter-substitution-2.html

#!/usr/bin/env bash

set -o errexit -o nounset -o pipefail



BAR_A_ROOT=1
BAR_A_PATHS=2
BAR_B_ROOT=3
BAR_C_PATHS=4
BAR_D_ROOT=5
BAR_D_PATHS=6


for VAR in ${!BAR_*}
do
    VALUE=${!VAR}
    V=${VAR#BAR_}
    ONE=${V%%_*}
    TWO=${V##*_}
    echo \'$ONE\' \'$TWO\' \'$VALUE\'
done